Answer 2.10
Applying the ShannonHartley equation we obtain:
C = 3000.log2(103 + 1)
= 29.9 kbps
Note: the S/N ratio must be converted from dB
to a pure ratio, for example 30 dB is 103 when used in this equation.
In order to determine the number of symbol states
required to support this data rate, we can apply the expression:
C = 2B.log2M (for a baseband channel)
hence:
M = 2C/2B = 31.6 (32) signalling
states required.