Example 5.2
A coherent ASK demodulator has a 5o error in its locally
generated carrier reference. What will be the degradation in noise power immunity compared
with an ideal demodulator?
Solution
The voltage output of the mixer used to compare the incoming symbol
a(t) cos wct
with the reference
cos(wct + 5o)
will be reduced by a factor cos(5o) from its maximum value as
a result of the carrier phase error.
This in turn equates to a reduction in symbol energy
at the input to the receiver of cos2(5o). (Symbol energy is proportional to
power x symbol length or voltage2 x symbol length.)
The noise components passing through the mixer will
also be affected by the phase error in the carrier reference, but since the noise vectors
are assumed to be randomly distributed through 360o, the carrier phase error
will reduce the effect of some noise vectors and enhance others with the net effect that
the average noise voltage at the mixer output will remain unchanged.
Hence it is only the symbol energy that is truly affected by carrier reference phase error and not the noise
power. This means that the effective received symbol energy
to noise power density will be reduced by a factor 1 / cos2(5o)
= 1.0076, or 0.0033 dB as a result of the phase error.